C) the horizontal component of the ball's velocity D) the vertical component of the ball's velocity 15.A ball is thrown with a velocity of 35 meters per second at an angle of 30° above the horizontal. Which quantity has a magnitude of zero when the ball is at the highest point in its trajectory? A) 7.71 m/s B) 9.20 m/s C) 15.7 m/s D) 18.7 m/s
13-2. The 10-lb block has an initial velocity of 10 ft>s on the v = 10 ft/s smooth plane. If a force F = 12.5t2 lb Determine the constant horizontal force developed in the coupling C, and the frictional force developed between *13-16. The man pushes on the 60-lb crate with a force F. The force is...

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A horizontal force F acts on a block that is connected to another block by a string. Blocks A and B are connected by massless String 2 and pulled across a frictionless surface by massless String 1. The mass of B is An object in translational equilibrium is either at rest or moving with a constant velocity.
If the car is moving at constant velocity, the total horizontal force is zero; so F = D, the magnitude of the air resistance (drag) force. If the car is accelerating forwards, there is a net force component F - D forwards. b) The total force that the road exerts on the car must provide a component directed towards the centre of the curve.

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Let's say 10 kg block is sliding on a frictionless surface at a constant velocity, thus its acceleration is 0. According to Newton's second law of motion, the force acting on the block is 0:
A crate is pushed at constant velocity across a rough, horizontal surface by a push force P. The crate has a weight of 73N. Coefficient of kinetic friction between the crate and the floor is 0.41. Vector force P points at an angle of 37 degrees below the horizontal. What is the magnitude of the normal force? Homework Equations f k = μ k N

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A block rests on top of a table- Consider only the forces acting upon the block A block is being pushed across the top of a table. Consider only the forces acting upon the block Force Present (P) or Absent (A)? Explanation 5. 6- Gravity Spling. Tension Normal. Fliction Ail Res.: Gravity ; Spring. Tension : Nonnal- Fliction Air Res.: P or A. or ...
If you push with force F on ... A 10.0-kg box is pulled along a horizontal surface by a force of 40.0 N applied at a ... is constant: The magnitude of the velocity .

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Straight-line motion with constant force An iceboat is at rest on a perfectly frictionless horizontal surface. A steady wind is blowing so that 4.0s after the iceboat is released, it attains a velocity of 6.0 m/s. The iceboat and rider have a combined mass of 200 kg. What constant horizontal force F W does the wind exert on the iceboat?
Two blocks rest on a horizontal frictionless surface as shown. The surface between the top and bottom blocks is roughened so that there is no slipping between the two blocks. A 30-N force is applied to the bottom block as suggested in the figure. 13. What is the acceleration of the "two block" system? A) 1 m/s2 B) 2 m/s2 C) 3 m/s2 D) 6 m/s2 E ...

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60. A 4.00-kg block is pushed along the ceiling with a constant applied force of 85.0 N that acts at an angle of 55.0° with the horizontal, as in Figure P4.60. The block accelerates to the right at 6.00 m/s2. Determine the coefficient of kinetic friction between block and ceiling.
being slid at constant speed across a horizontal concrete oor by a force parallel to the oor. Which pair of quantities could be used to determine the coe cient of friction for the granite on the concrete? A. mass and speed of the block B. mass and normal force on the block C. frictional force and speed of the block D. frictional force and ...

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accelerate the same block across a frictionless floor. Rank the situations according to the magnitudes of (a) the net force on the block and (b) the acceleration of the block, greatest first. Sample 2 A 2.0 kg cookie tin is accelerated at 3.0 m/s2 in the direction shown by a, over a frictionless horizontal surface. The acceleration is caused by ...
Two blocks I and II have masses m and 2m respectively. Block II has an ideal massless spring (with force constant, k) attached to one side and is initially stationary while block I approaches it across a frictionless, horizontal surface with a speed v o. All momentum and energy initially belong to block I.

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Constant velocity Counter force that appears when an external force tends to slide a body along a surface. It is directed parallel to the surface and opposite to the sliding motion. F (applied force) f s F // -Static: (f s) compensates the applied force, the body does not move.
A 50.-newton horizontal force is needed to keep an object weighing 500. newtons moving at a constant velocity of 2.0 meters per second across a horizontal surface. The magnitude of the frictional force acting on the object is A. 500.N B. 450.N C. 50.N D. 0N 13.

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1) A block lies on a horizontal frictionless surface. A horizontal force of 100 N is applied to the block giving rise to an acceleration of 3.0 m/s2. (a) Determine the mass of the block. (b) Calculate the distance the block will travel if the force is applied for 10 s.
Jan 09, 2013 · A 10kg block is pushed across a horizontal surface with a horizontal force of 20N against a friction force of 10N. The acceleration of the block in meters per second per second is A.

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kg, and the coefficient of kinetic friction between the sled and the surface is 0.100, with what force do you need to push in order for the sled to move with constant velocity? 241 N Supporting Materials 16.-Question Details OSColPhys1 5.P.025.WA. [2613433] Physical Constants A block of mass m 1 = 35 kg on a horizontal surface is connected to a ...
Draw a free body diagram for a crate being pushed across a flat surface at a constant speed When one object rests on another…a force is present that keeps the object from falling through. normal force (F n )– the force that acts on a surface directly perpendicular to that surface.
Answer. The block moves with constant velocity on horizontal surface, this indicates the acceleration of block is zero Fnet= 0 Taking right direction as positive force direction 5 N + f N+ (-3) N=0 => f= -2 N where f is frictional force. the frictional force value is 2N in leftward direction, hence...
This block will identify background information the student should already possess. Thrust is the force produced by the hot gas coming out the back of the engine. Constant velocity implies not only constant speed, but, unchanging direction as well.

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